PHP:pg_field_table()的用法_PostgreSQL函数

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pg_field_table

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(PHP 5 >= 5.2.0)

pg_field_table — Returns the name or oid of the tables field

说明 mixed pg_field_table ( resource $result , int $field_number [, bool $oid_only = false ] )

pg_field_table() returns the name of the table that field belongs to, or the table&#;s oid if oid_only is TRUE.

参数

result

PostgreSQL query result resource, returned by pg_query(), pg_query_params() or pg_execute() (among others).

field_number

Field number, starting from 0.

oid_only

By default the tables name that field belongs to is returned but if oid_only is set to TRUE, then the oid will instead be returned.

返回值

On success either the fields table name or oid. Or, FALSE on failure.

范例

Example #1 Getting table information about a field

<?php$dbconn=pg_connect("dbname=publisher")ordie("Couldnotconnect");$res=pg_query($dbconn,"SELECTbarFROMfoo");echopg_field_table($res,0);echopg_field_table($res,0,true);$res=pg_query($dbconn,"SELECTversion()");var_dump(pg_field_table($res,0));?>

以上例程的输出类似于：

注释

Note:

Returning the oid is much faster than returning the table name because fetching the table name requires a query to the database system table.

参见

pg_field_name() - 返回字段的名字 pg_field_type() - 返回相应字段的类型名称

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