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PHP:pg_field_type_oid()的用法_PostgreSQL函数
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(PHP 5 >= 5.1.0)
pg_field_type_oid — Returns the type ID (OID) for the corresponding field number
说明 int pg_field_type_oid ( resource $result , int $field_number )pg_field_type_oid() returns an integer containing the OID of the base type of the given field_number in the given PostgreSQL result resource.
You can get more information about the field type by querying PostgreSQL&#;s pg_type system table using the OID obtained with this function. The PostgreSQL format_type() function will convert a type OID into an SQL standard type name.
Note:
If the field uses a PostgreSQL domain (rather than a basic type), it is the OID of the domain&#;s underlying type that is returned, rather than the OID of the domain itself.
参数
result
PostgreSQL query result resource, returned by pg_query(), pg_query_params() or pg_execute() (among others).
field_numberField number, starting from 0.
返回值The OID of the field&#;s base type. FALSE is returned on error.
范例
Example #1 Getting information about fields
<?php$dbconn=pg_connect("dbname=publisher")ordie("Couldnotconnect");//Assume'title'isavarchartype$res=pg_query($dbconn,"selecttitlefromauthorswhereauthor='Orwell'");echo"TitlefieldtypeOID:",pg_field_type_oid($res,0);?>以上例程会输出：
参见pg_field_type() - 返回相应字段的类型名称 pg_field_prtlen() - 返回打印出来的长度 pg_field_name() - 返回字段的名字
PHP:pg_field_size()的用法_PostgreSQL函数 pg_field_size(PHP4=4.2.0,PHP5)pg_field_size返回指定字段占用内部存储空间的大小说明intpg_field_size(resource$result,int$field_number)pg_field_size()返回PostgreSQLresult中指定字
PHP:pg_field_prtlen()的用法_PostgreSQL函数 pg_field_prtlen(PHP4=4.2.0,PHP5)pg_field_prtlen返回打印出来的长度说明intpg_field_prtlen(resource$result,int$row_number,string$field_name)pg_field_prtlen()返回PostgreSQLresult中得到的
PHP:pg_field_num()的用法_PostgreSQL函数 pg_field_num(PHP4=4.2.0,PHP5)pg_field_num返回字段的编号说明intpg_field_num(resource$result,string$field_name)pg_field_num()返回给定PostgreSQLresult资源中的field_name所代表的列（
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