【工作流Activiti7】3、Activiti7 回退与会签(工作流activity)

【工作流Activiti7】3、Activiti7 回退与会签

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1.  回退（驳回）

回退的思路就是动态更改节点的流向。先遇水搭桥，最后再过河拆桥。

具体操作如下：

取得当前节点的信息取得当前节点的上一个节点的信息保存当前节点的流向新建流向，由当前节点指向上一个节点将当前节点的流向设置为上面新建的流向当前节点完成任务将当前节点的流向还原取得之前上个节点的执行人设置上个节点的assignee为之前的执行人

代码实现起来可能是这样的： 

@Testpublic void huitui() throws Exception { ProcessEngine processEngine = ProcessEngines.getDefaultProcessEngine(); TaskService taskService = processEngine.getTaskService(); Task task = taskService.createTaskQuery().processInstanceId("55001").singleResult(); backProcess(task);}/** * 驳回 / 回退 * 按照这种方法，可以回退至任意节点 * @param task * @throws Exception */public void backProcess(Task task) throws Exception { ProcessEngine processEngine = ProcessEngines.getDefaultProcessEngine(); HistoryService historyService = processEngine.getHistoryService(); RepositoryService repositoryService = processEngine.getRepositoryService(); TaskService taskService = processEngine.getTaskService(); String processInstanceId = task.getProcessInstanceId(); // 获取所有历史任务（按创建时间降序） List<HistoricTaskInstance> hisTaskList = historyService.createHistoricTaskInstanceQuery() .processInstanceId(processInstanceId) .orderByTaskCreateTime() .desc() .list(); List<HistoricActivityInstance> hisActivityList = historyService.createHistoricActivityInstanceQuery() .processInstanceId(processInstanceId).list(); if (CollectionUtils.isEmpty(hisTaskList) || hisTaskList.size() < 2) { return; } // 当前任务 HistoricTaskInstance currentTask = hisTaskList.get(0); // 前一个任务 HistoricTaskInstance lastTask = hisTaskList.get(1); // 当前活动 HistoricActivityInstance currentActivity = hisActivityList.stream().filter(e -> currentTask.getId().equals(e.getTaskId())).collect(Collectors.toList()).get(0); // 前一个活动 HistoricActivityInstance lastActivity = hisActivityList.stream().filter(e -> lastTask.getId().equals(e.getTaskId())).collect(Collectors.toList()).get(0); BpmnModel bpmnModel = repositoryService.getBpmnModel(task.getProcessDefinitionId()); // 获取前一个活动节点 FlowNode lastFlowNode = (FlowNode) bpmnModel.getMainProcess().getFlowElement(lastActivity.getActivityId()); // 获取当前活动节点 FlowNode currentFlowNode = (FlowNode) bpmnModel.getMainProcess().getFlowElement(currentActivity.getActivityId()); // 临时保存当前活动的原始方向 List<SequenceFlow> originalSequenceFlowList = new ArrayList<>(); originalSequenceFlowList.addAll(currentFlowNode.getOutgoingFlows()); // 清理活动方向 currentFlowNode.getOutgoingFlows().clear(); // 建立新方向 SequenceFlow newSequenceFlow = new SequenceFlow(); newSequenceFlow.setId("newSequenceFlowId"); newSequenceFlow.setSourceFlowElement(currentFlowNode); newSequenceFlow.setTargetFlowElement(lastFlowNode); List<SequenceFlow> newSequenceFlowList = new ArrayList<>(); newSequenceFlowList.add(newSequenceFlow); // 当前节点指向新的方向 currentFlowNode.setOutgoingFlows(newSequenceFlowList); // 完成当前任务 taskService.complete(task.getId()); // 重新查询当前任务 Task nextTask = taskService.createTaskQuery().processInstanceId(processInstanceId).singleResult(); if (null != nextTask) { taskService.setAssignee(nextTask.getId(), lastTask.getAssignee()); } // 恢复原始方向 currentFlowNode.setOutgoingFlows(originalSequenceFlowList);}

以请假为例

<process id="holiday" name="holiday" isExecutable="true"> <startEvent id="startevent1" name="Start"></startEvent> <userTask id="usertask1" name="填写请假单" activiti:assignee="${assignee1}"></userTask> <sequenceFlow id="flow1" sourceRef="startevent1" targetRef="usertask1"></sequenceFlow> <userTask id="usertask2" name="部门经理审批" activiti:assignee="${assignee2}"></userTask> <sequenceFlow id="flow2" sourceRef="usertask1" targetRef="usertask2"></sequenceFlow> <userTask id="usertask3" name="人事审批" activiti:candidateUsers="tom,jerry"></userTask> <sequenceFlow id="flow3" sourceRef="usertask2" targetRef="usertask3"></sequenceFlow> <endEvent id="endevent1" name="End"></endEvent> <sequenceFlow id="flow4" sourceRef="usertask3" targetRef="endevent1"></sequenceFlow></process>

假设现在已经到“人事审批”这个节点了，当前活动是usertask3

接下来，我们运行上面的代码，回退到上一个节点“部门经理审批”，于是

流程重新从“部门经理审批”节点开始往下走，当流程走完以后

证明，思路正确，写法没啥问题。但是，上面的代码可以简化一下，如下：

/** * 跳到最开始的任务节点（直接打回） * @param task 当前任务 */public void jumpToStart(Task task) { ProcessEngine processEngine = ProcessEngines.getDefaultProcessEngine(); HistoryService historyService = processEngine.getHistoryService(); RepositoryService repositoryService = processEngine.getRepositoryService(); TaskService taskService = processEngine.getTaskService(); String processInstanceId = task.getProcessInstanceId(); // 获取所有历史任务（按创建时间升序） List<HistoricTaskInstance> hisTaskList = historyService.createHistoricTaskInstanceQuery() .processInstanceId(processInstanceId) .orderByTaskCreateTime() .asc() .list(); if (CollectionUtils.isEmpty(hisTaskList) || hisTaskList.size() < 2) { return; } // 第一个任务 HistoricTaskInstance startTask = hisTaskList.get(0); // 当前任务 HistoricTaskInstance currentTask = hisTaskList.get(hisTaskList.size() - 1); BpmnModel bpmnModel = repositoryService.getBpmnModel(task.getProcessDefinitionId()); // 获取第一个活动节点 FlowNode startFlowNode = (FlowNode) bpmnModel.getMainProcess().getFlowElement(startTask.getTaskDefinitionKey()); // 获取当前活动节点 FlowNode currentFlowNode = (FlowNode) bpmnModel.getMainProcess().getFlowElement(currentTask.getTaskDefinitionKey()); // 临时保存当前活动的原始方向 List<SequenceFlow> originalSequenceFlowList = new ArrayList<>(); originalSequenceFlowList.addAll(currentFlowNode.getOutgoingFlows()); // 清理活动方向 currentFlowNode.getOutgoingFlows().clear(); // 建立新方向 SequenceFlow newSequenceFlow = new SequenceFlow(); newSequenceFlow.setId("newSequenceFlowId"); newSequenceFlow.setSourceFlowElement(currentFlowNode); newSequenceFlow.setTargetFlowElement(startFlowNode); List<SequenceFlow> newSequenceFlowList = new ArrayList<>(); newSequenceFlowList.add(newSequenceFlow); // 当前节点指向新的方向 currentFlowNode.setOutgoingFlows(newSequenceFlowList); // 完成当前任务 taskService.complete(task.getId()); // 重新查询当前任务 Task nextTask = taskService.createTaskQuery().processInstanceId(processInstanceId).singleResult(); if (null != nextTask) { taskService.setAssignee(nextTask.getId(), startTask.getAssignee()); } // 恢复原始方向 currentFlowNode.setOutgoingFlows(originalSequenceFlowList);}

2.  会签

多个人同时处理一个任务，这种任务我们称之为会签任务 。Activiti实现会签是基于多实例任务，将节点设置成多实例，主要通过在UserTask节点的属性上配置。

会签的种类：

按数量通过： 达到一定数量的通过表决后，会签通过。按比例通过： 达到一定比例的通过表决后，会签通过。一票否决： 只要有一个表决时否定的，会签通过。一票通过： 只要有一个表决通过的，会签通过。

每个实例有以下变量：

nrOfInstances: 实例总数

nrOfActiveInstances: 当前激活的（未完成的）实例总数。 如果串行执行，则改值永远是1

nrOfCompletedInstances: 已完成的实例总数

条件${nrOfInstances == nrOfCompletedInstances}表示所有人员审批完成后会签结束。

条件${ nrOfCompletedInstances == 1}表示一个人完成审批，该会签就结束。

其他条件依次类推，同时这里也可以写自己添加的流程变量。

相关文档如下：

下面举个例子：

<process id="countersign" name="countersign" isExecutable="true"> <startEvent id="startevent1" name="Start"></startEvent> <userTask id="usertask1" name="申请" activiti:assignee="zhangsan"></userTask> <sequenceFlow id="flow1" sourceRef="startevent1" targetRef="usertask1"></sequenceFlow> <userTask id="usertask2" name="会签审批" activiti:assignee="${approver}"> <multiInstanceLoopCharacteristics isSequential="false" activiti:collection="${approverList}" activiti:elementVariable="approver"> <completionCondition>${nrOfCompletedInstances == nrOfInstances}</completionCondition> </multiInstanceLoopCharacteristics> </userTask> <sequenceFlow id="flow2" sourceRef="usertask1" targetRef="usertask2"></sequenceFlow> <userTask id="usertask3" name="备案" activiti:assignee="tianqi"></userTask> <sequenceFlow id="flow3" sourceRef="usertask2" targetRef="usertask3"></sequenceFlow> <endEvent id="endevent1" name="End"></endEvent> <sequenceFlow id="flow4" sourceRef="usertask3" targetRef="endevent1"></sequenceFlow></process>

编写代码：

// 部署流程定义RepositoryService repositoryService = processEngine.getRepositoryService();Deployment deployment = repositoryService.createDeployment() .addClasspathResource("diagram/countersign.bpmn") .name("会签示例") .key("countersign") .deploy();// 启动流程实例RuntimeService runtimeService = processEngine.getRuntimeService();Map<String, Object> variables = new HashMap<>();variables.put("approverList", Arrays.asList("lisi","wangwu","zhaoliu"));ProcessInstance processInstance = runtimeService.startProcessInstanceByKey("countersign", variables);// 完成任务TaskService taskService = processEngine.getTaskService();Task task = taskService.createTaskQuery().processInstanceId("107501").taskAssignee("zhaoliu").singleResult();if (null != task) { taskService.complete(task.getId());}

流程启动后，首先是zhangsan审批

当zhangsan完成自己的任务后，进入会签环节，于是我们看到当前有3个激活的任务

当lisi完成任务以后，当前任务剩下2个

当wangwu和zhaoliu都完成任务了以后，会签任务完成，进入下一个环节

刚才的例子中没有考虑到审批不通过的情况，接下来我们完善一下，考虑下面的流程

<process id="countersign" name="countersign" isExecutable="true"> <startEvent id="startevent1" name="Start"></startEvent> <userTask id="usertask1" name="申请" activiti:assignee="zhangsan"></userTask> <sequenceFlow id="flow1" sourceRef="startevent1" targetRef="usertask1"></sequenceFlow> <userTask id="usertask2" name="会签审批" activiti:assignee="${approver}"> <multiInstanceLoopCharacteristics isSequential="false" activiti:collection="${approverList}" activiti:elementVariable="approver"> <completionCondition>${nrOfCompletedInstances / nrOfInstances == 1 || pass == false}</completionCondition> </multiInstanceLoopCharacteristics> </userTask> <sequenceFlow id="flow2" sourceRef="usertask1" targetRef="usertask2"></sequenceFlow> <userTask id="usertask3" name="备案" activiti:assignee="tianqi"></userTask> <exclusiveGateway id="exclusivegateway1" name="Exclusive Gateway"></exclusiveGateway> <sequenceFlow id="flow5" sourceRef="usertask2" targetRef="exclusivegateway1"></sequenceFlow> <sequenceFlow id="flow6" name="通过" sourceRef="exclusivegateway1" targetRef="usertask3"> <conditionExpression xsi:type="tFormalExpression"><![CDATA[${pass == true}]]></conditionExpression> </sequenceFlow> <sequenceFlow id="flow7" name="拒绝" sourceRef="exclusivegateway1" targetRef="usertask1"> <conditionExpression xsi:type="tFormalExpression"><![CDATA[${pass == false}]]></conditionExpression> </sequenceFlow> <endEvent id="endevent1" name="End"></endEvent> <sequenceFlow id="flow8" sourceRef="usertask3" targetRef="endevent1"></sequenceFlow></process>

在会签审批完成任务时就要加上流程变量pass了

RuntimeService runtimeService = processEngine.getRuntimeService();TaskService taskService = processEngine.getTaskService();Task task = taskService.createTaskQuery().processInstanceId("152501").taskAssignee("lisi").singleResult();if (null != task) { Map<String, Object> variables = new HashMap<>(); variables.put("pass", true);// variables.put("pass", false); taskService.complete(task.getId(), variables); runtimeService.getVariable(task.getExecutionId(), "nrOfCompletedInstances");}

zhaoliu审批的时候pass传的false，于是流程又走到zhangsan那里，流程重新又走了一遍才全部完成

回退和会签就先讲到这里